16x^2+61x-42=0

Solution for 16x^2+61x-42=0 equation:

16x^2+61x-42=0

a = 16; b = 61; c = -42;
Δ = b2-4ac
Δ = 612-4·16·(-42)
Δ = 6409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{6409}}{2*16}=\frac{-61-\sqrt{6409}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{6409}}{2*16}=\frac{-61+\sqrt{6409}}{32}
$